pipes

This is NOT UNIX PIPES

Pipe operator takes the value on the left side and passes it as the first argument to the function on the right side. It transforms nested code like f(g(h(x))) into a readable sequence: x |> h() |> g() |> f().

function append1(data : string) do
    return data + "1";
end

function append2(data : string) do
    return data + "2";
end

var result : int = ( 10 |>
            Type.Converter.toString |>
            append1 |>
            append2 |>
            Type.Converter.toInt );

println result; // 1012 (int)

Expressions that are not the first element of the pipe, breaks the pipe and new pipe forms after that expression.

For example :

function append1(data : string) do
    return data + "1";
end

function append2(data : string) do
    return data + "2";
end

var result : int = ( 10 |>
            Type.Converter.toString |> // convert to int
            append1 |> // 101
            50 |> // pipe breaks new output is 50
            Type.Converter.toString |>
            append2 |> // 502
            Type.Converter.toInt // convert to int 502 
            );

println result; // 502 (int)